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public class Double_isFiniteMethodExample1 { public static void main(String[] args) { double d1 = 99991.22; Double d2 = new Double(d1/0); if(Double.isFinite(d2)){ System.out.println("Value returned is : " +Double.isFinite(d2)); } else{ System.out.println("Value returned is : "+Double.isFinite(d2)); } } }
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